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6x^2-972=0
a = 6; b = 0; c = -972;
Δ = b2-4ac
Δ = 02-4·6·(-972)
Δ = 23328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23328}=\sqrt{11664*2}=\sqrt{11664}*\sqrt{2}=108\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108\sqrt{2}}{2*6}=\frac{0-108\sqrt{2}}{12} =-\frac{108\sqrt{2}}{12} =-9\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108\sqrt{2}}{2*6}=\frac{0+108\sqrt{2}}{12} =\frac{108\sqrt{2}}{12} =9\sqrt{2} $
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